![]() Retrieving a list of all database tables in PostgreSQL is essential for understanding the structure and contents of your database. ![]() Tip: you can split the diagram into sub-diagrams according to schemas, add notes and other information etc. Learn more about visualization of existing PostgreSQL databases. Just create a database connection:Īnd then click on Connect and load existing structure. The advantage is greater clarity, the ability to search, view details, view SQL scripts and identify dependencies.Ĭreating an ER diagram in Luna Modeler is easy. Using Luna Modeler to show tables in PostgresĪnother option is to display all tables of the selected database using an ER diagram. Execute the query, and the result will display a list of all tables within the database.This query retrieves the names of all base tables from the information_schema.tables view, excluding system tables. ![]() Connect to your PostgreSQL database using the appropriate credentials.ĪND table_schema NOT IN ('pg_catalog', 'information_schema').Open your favorite PostgreSQL client, such as pgAdmin or any other database management tool.Type the following to display a list of all tables in the current database:.Replace database_name with one of the available databases. Then type this command to switch to the database.Once you’re in the psql terminal, enter the following command to list all databases.Replace your_username with your PostgreSQL username. Type the following command to access the psql interactive terminal: In this article, we will explore a few methods to show all database tables in PostgreSQL. This information is useful for understanding the structure of your database. WHERE acl_antor_oid acl_base.Introduction: In PostgreSQL, a popular and powerful open-source relational database management system, there are times when you need to retrieve a list of all tables within a database. ( aclexplode ( acl ) ).is_grantable AS is_grantable ( aclexplode ( acl ) ).privilege_type AS privilege_type, ( aclexplode ( acl ) ).grantee AS grantee_oid, ( aclexplode ( acl ) ).grantor AS grantor_oid, ON ( schemas.schema_oid = t.typnamespace )Ĭoalesce ( p.fdwacl, acldefault ( 'F'::"char", p.fdwowner ) ) AS aclĬoalesce ( p.srvacl, acldefault ( 'S'::"char", p.srvowner ) ) AS acl ON ( schemas.schema_oid = p.pronamespace )Ĭoalesce ( t.typacl, acldefault ( 'T'::"char", t.typowner ) ) AS acl Pg_catalog.pg_get_function_arguments ( p.oid ) AS calling_arguments,Ĭoalesce ( p.proacl, acldefault ( 'f'::"char", p.proowner ) ) AS acl WHERE c.relkind IN ( 'r', 'v', 'm', 'S', 'f', 'p' )Ĭ.object_name || '.' || a.attname::text AS object_name,Ĭoalesce ( a.attacl, acldefault ( 'c'::"char", c.owner_oid ) ) AS acl ON ( schemas.schema_oid = c.relnamespace ) WHEN c.relkind = 'S' THEN coalesce ( c.relacl, acldefault ( 's'::"char", c.relowner ) )ĮLSE coalesce ( c.relacl, acldefault ( 'r'::"char", c.relowner ) ) WHEN c.relkind = 'I' THEN 'partitioned index' WHEN c.relkind = 'p' THEN 'partitioned table' WHEN c.relkind = 'f' THEN 'foreign table' ![]() WHEN c.relkind = 'm' THEN 'materialized view' WITH rol AS (Ĭoalesce ( n.nspacl, acldefault ( 'n'::"char", n.nspowner ) ) AS acl This updated query also contains column grants and function/procedure signatures. Updated to add an updated query that uses the pg catalog tables instead of the information_schema views. WHERE rug.udt_schema NOT IN ( 'pg_catalog', 'information_schema' )ĪND substr ( rug.udt_schema, 1, 3 ) 'pg_' WHERE rrg.specific_schema NOT IN ( 'pg_catalog', 'information_schema' )įROM information_schema.role_udt_grants rug ON ( fcn.routine_catalog = rrg.routine_catalogĪND fcn.routine_schema = rrg.routine_schemaĪND fcn.routine_name = rrg.routine_name ) LEFT JOIN information_schema.routines fcn WHERE rtg.table_schema NOT IN ( 'pg_catalog', 'information_schema' )įROM information_schema.role_routine_grants rrg ON ( tab.table_catalog = rtg.table_catalog WHERE rug.object_schema NOT IN ( 'pg_catalog', 'information_schema' )įROM information_schema.role_table_grants rtg While the following is not a complete solution (column privs aren't included, it doesn't have the function signatures) you should hopefully be able to get most of what you're asking for using: SELECT rug.grantor,įROM information_schema.role_usage_grants rug ![]()
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